The dipole moment of `HBr` is ` 1.6 xx 10^(-30) cm` and interatomic spacing is `1 Å`. The `%` ionic character of `HBr` is

Options

A. 7
B. 10
C. 15
D. 27

Answer

B

Explanation

Charge of `e^(-) = 1.6 xx 10^(-19)`
Dipole moment of `HBr = 1.6 xx 10^(-30)`
Inter atomic spacing `= 1Å = 1 xx 10^(-10) m`
% of ionic character in
`HBr = ("dipole moment of "HBr xx 100)/("inter spacing distance" xxq)`
` = (1.6 xx 10^(-30))/(1.6 xx 10^(-19) xx 10^(-10)) xx 100`
` = 10^(-3) xx 10^(29) xx 100 = 10^(-1) xx 100 = 0.1 xx 100 = 10%`