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If the molecule of HCl were totally pola...

If the molecule of HCl were totally polar, the observed value of dipole moment is 1.03 D (debye) but the experimental value of dipole moment was 6.12 D. Calculate the percentage ionic character.

A

17

B

83

C

50

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A
% of ionic character
` = ("Experimental value of dipole moment")/("Expected value of dipole moment")`
`= (1.03)/(6.12) xx 100 = 16.83%~~ 17%`
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