Consider the molecules `CH_(4),NH_(3)` and `H_(2)O` which of the given statement is false ?

Options

A. The H – C – H bond angle in , `CH_4,` the H - N - H bond angle in `NH_3`, and the `H - O - H` bond angle in `H_2O` are all greater than `90^@`
B. The `H - O - H` bond angle in `H_2O` is larger than the `H - C - H` bond angle in `CH_4`
C. The H - O - H bond angle in `H_2O` is smaller than the H- N - H bond angle in `NH_3`
D. The H - C - H bond angle in `CH_4` is larger than the H - N - H bond angle in `NH_3`

Answer

B

Explanation

In all the three cases, central atom is `sp^3` hybridized but due to lone pair of electrons (lp-lp and lp -lp repulsions) bond angle is less in `NH_3 and H_2O` than regular tetrahedron structure.