Home
Class 11
CHEMISTRY
Concentration of CN^(-) " in " 0.1 M HCN...

Concentration of `CN^(-) " in " 0.1` M HCN is (Given :`K_(a) = 4 xx 10^(-10)`)

A

`2.5 xx 10^(-6)M `

B

`4.5 xx 10^(-6) M `

C

`6.3 xx 10^(-6) M`

D

`9.2 xx 10^(-6) M `

Text Solution

Verified by Experts

The correct Answer is:
C
`HCN hArr H^(+) +CN^(-)`
`K_(a)= ([H^(+)][CN^(-)])/([HCN])`
`[H^(+)]=[CN^(-)]=a `
`a^(2) =K_(a).[HCN]`
`= 4xx10^(-10) xx0.1`
` a= 6.3 xx 10^(-6)`
Promotional Banner

Topper's Solved these Questions

  • IONIC EQUILIBRIUM

    ERRORLESS|Exercise NCERT BASED QUESTIONS (ACIDS AND BASES)|78 Videos

  • IONIC EQUILIBRIUM

    ERRORLESS|Exercise NCERT BASED QUESTIONS (COMMON ION EFFECT, ISOHYDRIC SOLUTIONS, SOLUBILITY PRODUCT, IONIC PRODUCT OF WATER AND SALT HYDROLYSIS)|59 Videos

  • HYDROGEN

    ERRORLESS|Exercise ASSERTION & REASON|6 Videos

  • PURIFICATION, CLASSIFICATION AND NOMENCLATURE OF ORGANIC COMPOUNDS

    ERRORLESS|Exercise ASSERTION & REASON|9 Videos

Similar Questions

Explore conceptually related problems

What is the hydronium ion concentration of a 0.25 M HA solution (K_(a)=4xx10^(-8))

The increasing order of Ag^(+) ion concentration in I. Saturated solution of AgCl II. Saturated solution of Agl III. 1MAg(NH_(3))_(2)^(+)" in "0.1 M NH_(3) IV. 1MAg(CN)_(2)^(-)" in "0.1 M KCN Given : K_(sp)" of "AgCl=1.0xx10^(-10) K_(sp)" of "Agl=1.0xx10^(-16) K_(d)" of "Ag(NH_(3))_(2)^(+)=1.0xx10^(-8) K_(d)" of "Ag(CN)_(2)^(-)=1.0xx10^(-21)

What is the hydronium ion concentration of a 0.25 M HA solution? (K_(a)=4xx10^(-8))

What amount of HCl will be required to prepare one litre of a buffer solution of pH 10.4 using 0.01 mole of NaCN ? Given K_(ion)(HCN)=4.1xx10^(-10) .