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Degree of dissociation of 0.1 N CH(3)COO...

Degree of dissociation of 0.1 N `CH_(3)COOH`is ( Dissociation constant `=1xx 10^(-5))`

A

`10^(-5)`

B

`10^(-4)`

C

`10^(-3)`

D

`10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Degree of dissociation `alpha = ?`
Normality of solution = 0.1 N = `1/10 N`
Dissociation constant `K = 1 xx 10^(-5)`
`K = Calpha^(2), alpha = sqrt(K/C)`
`=sqrt((1xx10^(-5))/(0.1)) , alpha = 1 xx 10^(-2)` .
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