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A monoprotic acid in a 0.1 M solution io...

A monoprotic acid in a 0.1 M solution ionizes to `0.001%`. Its ionisation constant is

A

`1.0 xx 10^(-3)`

B

`1.0 xx 10^(-6)`

C

`1.0 xx 10^(-8)`

D

`1.0 xx 10^(-11)`

Text Solution

Verified by Experts

The correct Answer is:
D
` :. ` Monoprotic acid HA
`HA hArr H^(+) +A^(-)`
Ionisation constant = ?
`alpha = 0.001 % = (0.001)/100 = 10^(-5)`
`K=(alpha^(2))/V = ([10^(-5)]^(2))/10 = 10^(-11)`
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