The correct order of increasing `[H_3O^+]` in the following aqueous solution is :

Options

A. `0.01 " M " H_(2)S lt 0.01 " M " H_(2)SO_(4) lt 0.01 " M " NaCl lt 0.01 " M " NaNO_(2)`
B. `0.01 " M " NaCl lt 0.01 " M " NaNO_(2) lt 0.01 " M " H_(2)S lt 0.01 " M " H_(2)SO_(4)`
C. `0.01 " M " NaNO_(2) lt 0.01 " M " NaCl lt 0.01 " M " H_(2)S lt 0.01 " M " H_(2)SO_(4)`
D. `0.01 " M " H_(2)S lt 0.01 " M " NaNO_(2) lt 0.01 " M " NaCl lt 0.01 " M " H_(2)SO_(4)`

Answer

C

Explanation

`NaNO_(2)` is a salt of strong base and weak acid so its pH will be maximum. NaCl is neutral.`H_(2)SO_(4)`is most acidic.