The correct order of decreasing acidic nature of `H_(2)O, ROH, HC -= CH` and `NH_3)` is

Options

A. `CH -= CH gt H_(2)O gt ROH gt NH_(3)`
B. `H_(2)O gt ROH gt NH_(3)`
C. `ROH gt NH_(3) gt CH -= CH gt H_(2)O `
D. `H_(2)O gt ROH NH_(3) gt CH -= CH `

Answer

B

Explanation

`{:("Compound",pK_(a)),("ROH",(16-18)),(H_(2)O,14),(NH_(3),4.75(pK_(b))),(HC-=CH,26):}`
Smaller the `pK_(a)` stronger the acid .
` :. ` The order of decreasing acidic nature is
`H_(2)O gt ROH gt HC-= CH gt NH_(3)`