Why pure NaCl is precipitated when HCl gas is passed in saturated solution of NaCl

Options

A. Impurities dissolve in HCl
B. The value of `[Na^(+)] and [Cl^(-)]` becomes smaller than `K_(sp)` of NaCl
C. The value of `[Na^(+0] and [Cl^(-)]` becomes greater than`K_(sp)` of NaCl
D. HCl dissolves in the water

Answer

C

Explanation

`NaCl_((s))hArr Na_((aq))^(+) +Cl_(aq)^(-)`
`HCl hArr H^(+) +Cl^(-)`
The increase in `[Cl^(-)]` brings in an increase in `[Na^(+)] [Cl^(-)] ` which will lead for backward reaction because `K_(sp)NaCl = [Na^(+)][Cl^(-)] `.