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The solubility product of a sparingly so...

The solubility product of a sparingly soluble salt `AX_(2)` is `3.2xx10^(-11)`. Its solubility (in `mo//L`) is

A

`2 xx 10^(-4)`

B

` 4 xx 10^(-4)`

C

` 5.6 xx 10^(-6)`

D

` 3.1 xx 10^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
A
`underset (x) (AX_(2)) to underset (x) (A^(2+)) +2X^(-)`
`K_(sp) = 4x^(3), x = root3((3.2 xx 10^(-11))/4)`
` x = 2 xx 10^(-4) ` mole/L .
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