The solubility of silver chromate in `0.01 M K_(2) CrO_(4)" is " 2 xx 10^(-8)` mol/1. The solubility product of silver chromate will be

Options

A. `8 xx 10^(-24)`
B. `16 xx 10^(-24)`
C. `1.6 xx 10^(-18)`
D. `16 xx 10^(-18)`

Answer

D

Explanation

`{:("Given",K_(2)CrO_(4),hArr,2K^(+),+,"CrO"_(4)^(2-)),("Conc",0.01,,0.02,,0.01),("and for ",Ag_(2)CrO_(4),,,,):}`
`{:("Ag"_(2)CrO_(4),hArr,"2Ag"^(+),+,CrO_(4)^(2-)),(S,,"2S",,S+01):}`
`K_(sp) = [Ag^(+)][CrO_(4)^(2-)] `
`K_(sp) = (2S)^(2) (S+0.01) = 4S^(2) [S+0.01] `
`K_(sp) = 4 [ 2xx 10^(-8)]^(2) xx 0.01 [[2 xx 10^(-8)]^(2) lt lt 0.01] `
`K_(sp) = 4 xx 4 xx 0.01 xx 10^(-16) , K_(sp) = 16 xx 10^(-18)`