Calculate the hydrolysis constant of the salt containing `NO_(2)^(-)`. Given the `K_(a) " for " HNO_(2) = 4.5 xx 10^(-10)`

Options

A. `2.22 x 10^(-5)`
B. `4.44 xx 10^(-5)`
C. `2.22 xx 10^(-6)`
D. `4.44 xx 10^(-2)`

Answer

A

Explanation

The hydrolysis constant of the hydrolysis of salt of weak acid and strong base
`K_(h) = (K_(w))/(K_(a))`
Hence , hydolysis constant of salt with `NO_(2)^(-)` ion .
`K_(h) = (1 xx10^(-14))/(4.5 xx10^(-10)) = 2.22 xx10^(-5)`