The concentration of `[H^(+)]` and concentration of `[OH^(-)]` of a `0.1` aqueous solution of `2%` ionised weak acid is [Ionic product of water `=1xx10^(-14)`]

Options

A. `2xx10^(-3)M and 5 xx 10^(-12) M `
B. `1 xx 10^(3) M and 3 xx 10^(-11) M `
C. `0.02 xx 10^(-3) M and 5 xx 10^(-11)` M
D. ` 3 xx 10^(-2) M and 4 xx 10^(-13)` M

Answer

A

Explanation

Given that,
Concentration of solution =0.1
Degree of ionisation = 2 % = `2/100 = 0.02 `
Ionic product of water = ` 1xx 10^(-14)`
Concentration of `[H^(+)] ` = Concentration of solution X
Degree of ionisation = `0.1 xx 0.02 = 2xx 10^(-3) M `
Concentration of `[OH^(-)] = ("Ionic product of water ")/([H^(+)])`
`= (1 xx 10^(-14))/(2 xx 10^(-3)) = 0.5 xx 10^(-11) = 5 xx 10^(-12) M `