Given pH of a solution A is 3 and it is mixed with another solution B having pH 2. If both mixed then resultant pH of the solution will be

Options

A. `3.2`
B. `1.9`
C. `3.4`
D. `3.5`

Answer

B

Explanation

pH of the solution A = 3
`[H^(+)]_(A) = 10^(-3)M `
pH of the solution B = 2
`[H^(+)]_(B) = 10^(-2)M `
`[H^(+)] = 10^(-3)+10^(-2) = 10^(-3) +10 xx 10^(-3) = 11 xx 10^(-3)`
pH = -log (11xx10^(-3))=3-log 11 `
`= 3 - 1.04 = 1.95`