Equal volumes of three acid solutions of `pH 3, 4` and `5` are mixed in a vessel. What will be the `H^(+)` ion concentration in the mixture?

Options

A. `3.7 xx 10^(-3)`M
B. `1.11 xx 10^(-3)`M
C. `1.11 xx 10^(-4)` M
D. `3.7 xx 10^(-4)` M

Answer

D

Explanation

`[H^(+)]_(max) = (10^(-3)x+10^(-4)x +10^(-5)x)/(3x)`
`= 1/3 (10^(-3)+10^(-4)+10^(-5))=37 xx 10^(-5) = 3.7 xx 10^(-4)`