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0.023 g of sodium metal is reacted with ...

0.023 g of sodium metal is reacted with 100`cm^(3)` of water. The pH of the resulting solution is

A

10

B

11

C

9

D

12

Text Solution

Verified by Experts

The correct Answer is:
D
`M = (0.023 xx 1000)/(23 xx 100) = 0.01M `
`Na^(+) +OH^(-) hArr NaOH `
`[OH^(-)] = 0.01 M = 10^(-2) , pOH = - log (10^(-2)) = 2 `
`pH + pOH = 14 `
` :. pH = 14 - 2 = 12 `
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