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0.1 M HCl and 0.1 M H(2)SO(4), each of v...

0.1 M HCl and `0.1 M H_(2)SO_(4)`, each of volume 2 ml are mixed and the volume is made up to 6 ml by adding 2ml of 0.01 N NaCl solution. The pH of the resulting mixture is

A

`1.17`

B

`1.0`

C

`0.3`

D

`log 2 - log 3 `

Text Solution

Verified by Experts

The correct Answer is:
B
Millimoles of `H^(+) = 0.1 xx 2 + 0.1 xx 2 xx 2 = 0.6`
Total volume in mL = 6
`pH = - log [H^(+)] = -log ((0.6)/6) = - log 0.1 = 1.0`
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