The solubility product of `AgI` at `25^(@)C` is `1.0xx10^(-16) mol^(2) L^(-2)`. The solubility of `AgI` in `10^(-4) N` solution of `KI` at `25^(@)C` is approximately ( in `mol L^(-1)`)

Options

A. `1.0 xx 10^(-8)`
B. `1.0 xx 10^(-16)`
C. `1.0 xx 10^(-12)`
D. `1.0 xx 10^(-10)`

Answer

C

Explanation

`{:(KI,hArr,K^(+),+,I^(-),),(10^(-4),,0,,0, "Initial concentration"),(0,,10^(-4),,10^(-4),"Final concentration"),(Agl,hArr,"Ag"^(+),+,I^(-),),(,,S,,+ (S+10^(-4)),):}`
`K_(sp) = S(S+10^(-4))`
`S^(2) +10^(-4) xx S = 1 xx 10^(-16) rArr S = 10^(-12)`