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The ionization constant of ammonium hydr...

The ionization constant of ammonium hydroxide is `1.77xx10^(-5)` at `298 K`. Hydrolysis constant of ammonium chloride is

A

`5.65 xx 10^(-10)`

B

`6.50 xx 10^(-12)`

C

`5.65 xx 10^(-13)`

D

`5.65 xx 10^(-12)`

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(h) = (K_(w))/(K_(b)) = (1 xx 10^(-14))/(1.77 xx 10^(-5)) = 5.65 xx 10^(-10)`
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