Home
Class 11
CHEMISTRY
The solubility of BaSO(4) in water 2.42 ...

The solubility of `BaSO_(4)` in water `2.42 xx 10^(-3) gL^(-1)` at 298 K. The value of solubility product `(K_(sp))` will be (Given molar mass of `BASO_(4) = 233 g mol^(-1)`)

A

`1.08 xx 10^(-10) mol^(2)L^(-2)`

B

`1.08 xx 10^(-12)mol^(2)L^(-2)`

C

`1.08 xx 10^(-14) mol^(2)L^(-2)`

D

`1.08 xx 10^(-8) mol^(2)L^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Solubility `2.42 xx 10^(-3) "gL"^(-1)`
`S = (2.42)/(233) xx 10^(-3) " mol L"^(-1)`
`BaSO_(4) hArr underset (S) (Ba^(2+)) + underset (S) (SO_(4)^(2-))`
`K_(sp) = S^(2) = (2.42 /233xx10^(-3) " mol L"^(-1))^(2)`
`= 1.08 xx 10^(-10) "mol"^(2)L^(-2) `
Promotional Banner

Similar Questions

Explore conceptually related problems

The solubility of BaSO_(4) in water is 2.42xx10^(-3) gL^(-1) at 298 K . The value of its solubility product (K_(sp)) will be (Given molar mass of BaSO_(4)=233 g mol^(-1) )

The solubility of Sb_(2)S_(3) in water is 1.0 xx 10^(-5) mol/letre at 298K. What will be its solubility product ?

The solubility of Sb_(2)S_(3) in water is 1.0 xx 10^(-8) mol/litre at 298 K. What will be its solubility product:

The solubility of BaSO_(4) in water is 2.33xx10^(-3) g//litre . Its solubility product will be (molecular weight of BaSO_(4)=233 )

Solubility of CaF_(2) is 0.5xx10^(-4)" mol L"^(-1) . The value of K_(sp) for the salt is