The ionic product of water at `25^@C` is `10^(-14)` its ionic product at `90^@C` will be

Options

A. `1 xx 10^(-20)`
B. `1 xx 10^(-12)`
C. `1 xx 10^(-14)`
D. `1 xx 10^(-16)`

Answer

B

Explanation

On increasing the temperature the value of ionic product also increases.