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At 25^(@)C, the dissociation constant of...

At `25^(@)C`, the dissociation constant of a base. BOH is `1.0xx10^(-12)`. The concentration of hydroxyl ions in `0.01`M aqueous solution of the base would be

A

`2.0 xx 10^(-6) " mol L"^(-1)`

B

`1.0 xx 10^(-5) " mol L"^(-1)`

C

`1.0 xx 10^(-6) " mol L"^(-1)`

D

`1.0 xx 10^(-7) " mol L"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`{:(BOH,hArr,B^(+),+,OH^(-)),(C,,O,,O),(C(1-alpha),,Calpha,,Calpha):}`
`K_(b) = Calpha^(2)`
`alpha^(2) = 1 xx 10^(-12) //0.01 = 10^(-10) rArr alpha = 10^(-5)`
`[OH^(-)] = C.alpha = 0.01 xx 10^(-5) = 10^(-7) ` mol/L
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