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Calculate the pOH of solution at 25^(@)C...

Calculate the `pOH` of solution at `25^(@)C` that contains `1xx10^(-10) M` of hydronium ions, i.e., `H_(3)O^(+)`

A

`7.000`

B

`4.000`

C

`9.000`

D

`1.000`

Text Solution

Verified by Experts

The correct Answer is:
B
Given `H_(3)O^(+)` ion concentration = `1 xx 10^(-10)`
` pH = - log [H^(+)] , pH = - log [1 xx 10^(-10)] ` ,
`pH = + 10 log 10 , pH = 10 `
We know that , `pH + pOH = 14 " " …..(i)`
Put the value of pH in eq. (i)
`10 + pOH = 14 rArr pOH = 4 `
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