Home
Class 11
CHEMISTRY
40 ml of 0.1 M ammonia is mixed with 20 ...

40 ml of `0.1` M ammonia is mixed with 20 ml of `0.1 M HCI`. What is the pH of the mixture ? (`pK_(b)` of ammonia solution is `4.74.`)

A

`4.74`

B

`2.26`

C

`9.26`

D

`5.00`

Text Solution

Verified by Experts

The correct Answer is:
C
`{:(NH_(4)OH,+,HCl,hArr,NH_(4)Cl,+,H_(2)O,),(40 xx 0.1 ,,20 xx 0.1,,0,,0,"Intial concentration"),(4-2=2,,0,,2,,2," final concentration"):}`
Finally we have a basic buffer solution with equal concentration of weak base `NH_(4)OH` and salt `NH_(4)Cl` .
`pOH = pK_(b) + log. (["Salt"])/(["base"])`
`pOH = 4.74 ` [Salt ] = [Base ]
`pH = 14 - 4.74 = 9.26`
Promotional Banner

Similar Questions

Explore conceptually related problems

20 mL of 0.1N HCI is mixed with 20 ml of 0.1N KOH . The pH of the solution would be

5 mL of 0.4 N NaOH is mixed with 20 mL of 0.1 N HCl. The pH of the resulting solution will be

pH of when 50mL of 0.10 M ammonia solution is treated with 50 mL of 0.05 M HCI solution :- (pK_(b) "of ammonia"=4.74)

50 mL of 0.2M ammonia solution is treated with 25 mL of 0.2 M HCl. If pK_(b) of ammonia solution is 4.75 the pH of the mixture will be :

100 ml of 0.1 M CH_(3)COOH are mixed with 100ml of 0.1 M NaOH , the pH of the resulting solution would be