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A compound X, of boron reacts with NH(3)...

A compound X, of boron reacts with `NH_(3)` on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating and Y are represented by the formula.

A

`B_(2)H_(6), B_(3)N_(3)H_(6)`

B

`B_(2)O_(3), B_(3)N_(3)H_(6)`

C

`BF_(3), B_(3)N_(3)H_(6)`

D

`B_(3)N_(3)H_(6), B_(2)H_(6)`

Text Solution

Verified by Experts

The correct Answer is:
A
Reaction of ammonia with diborane gives initially `B_(2)H_(6).2NH_(3)` which is formulated as `[BH_(2)(NH_(3))_(2)]+ [BH_(4)]` further heating gives borazine, `B_(3)N_(3)H_(6)` also called borazole
`underset("Diborane (X)")(3B_(2)H_(6)) + 6NH_(3) overset(473K)rarr underset("Borazole (Y)")(2B_(3)N_(3)H_(6)) + 12H_(2)`
Borazole has cyclic structure and is isoelectronic and isosteric with benzene and thus called inorganic benzene or triborine triammine or borazine (ii) Diborane can be prepared by the reduction of `BF_(3)` with lithium aluminium hydride in diethyl ether.
`4BF_(3) + 3LiAlH_(4) rarr underset((X))(2B_(2)H_(6)) + 3AlF_(3) + 3LiF`
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