Which of the following statements is incorrect

Options

A. Aluminium reacts with excess NaOH to give `Al(OH)_(3)`
B. `NaHCO_(3)` on heating gives `Na_(2)CO_(3)`
C. Pure sodium metal dissolves in liquid ammonia to give blue solution
D. NaOH reacts with glass to give sodium silicate

Explanation

To determine which statement is incorrect, we will analyze each option provided in the question.

### Step-by-Step Solution:

1. **Analyze Option 1: Aluminium reacts with NaOH to give Al(OH)3.**
- The reaction of Aluminium (Al) with Sodium Hydroxide (NaOH) occurs in the presence of water. The balanced chemical equation for this reaction is:
\[ 2Al + 2NaOH + 6H_2O \rightarrow 2Na[Al(OH)_4] + 3H_2 \]
- This shows that Aluminium does not produce Al(OH)3 directly when reacting with NaOH; instead, it forms sodium aluminate (Na[Al(OH)4]). Therefore, this statement is incorrect.

2. **Analyze Option 2: Na2CO3 upon heating gives NaHCO3.**
- This statement is incorrect. When sodium carbonate (Na2CO3) is heated, it decomposes to form sodium oxide (Na2O) and carbon dioxide (CO2), not sodium bicarbonate (NaHCO3). The correct reaction is:
\[ 2Na_2CO_3 \rightarrow 2Na_2O + 2CO_2 + O_2 \]
- Therefore, this statement is also incorrect.

3. **Analyze Option 3: Pure sodium metal dissolving in liquid ammonia gives a blue solution.**
- This statement is correct. When sodium metal is dissolved in liquid ammonia, it forms solvated electrons, which impart a blue color to the solution. The reaction can be represented as:
\[ Na (s) \rightarrow Na^+ + e^- (solvated) \]
- Thus, this statement is correct.

4. **Analyze Option 4: NaOH reacts with glass to give sodium silicate.**
- This statement is correct. Sodium hydroxide reacts with silica (SiO2) in glass to form sodium silicate (Na2SiO3). The reaction can be represented as:
\[ SiO_2 + 2NaOH \rightarrow Na_2SiO_3 + H_2O \]
- Therefore, this statement is correct.

### Conclusion:
Based on the analysis, the incorrect statement is **Option 1**: "Aluminium reacts with NaOH to give Al(OH)3."