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An organic compound on analysis gave C=...

An organic compound on analysis gave `C=48 g,H=8g` and `N=56 g.` Volume of `1.0 g` of the compound was foud to be `200ml` at `NTP.` Molecular formula of the compound is

A

`C_(4)H_(8)N_(4)`

B

`C_(2)H_(4)N_(2)`

C

`C_(12)H_(24)N_(12)`

D

`C_(16)H_(32)N_(16)`

Text Solution

Verified by Experts

The correct Answer is:
A
`{:("Elements", %, "No. of moles", "Simple Ratio"),(C, 48, 48//12=4, 1),(H, 8, 8//1=8, 2),(N, 56, 56//14 =4, 1):}`
Empirical formula `= CH_(2)N`
Empirical formula mass = 28
Now, 200 mL of compound `1/200 xx 22400 = 112`
`n = ("Mol. mass")/("Emp. formula mass") = 112/28 = 4`
Therefore, Molecular formula `=(CH_(2)N)_(4) = 940 g`
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