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The amount of anhydrous Na2 CO3 present ...

The amount of anhydrous `Na_2 CO_3` present in 250 ml of 0.25 M solution is

A

6.225 g

B

66.25 g

C

6.0 g

D

6.625 g

Text Solution

Verified by Experts

The correct Answer is:
D
`M=(w)/(mxxV(l)),0.25=(w)/(106xx0.25)`
w = 6.625 g.
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