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The amount of anhydrous Na2 CO3 present ...

The amount of anhydrous `Na_2 CO_3` present in 250 ml of 0.25 M solution is

A

6.225 g

B

66.25 g

C

6.0 g

D

6.625 g

Text Solution

Verified by Experts

The correct Answer is:
D
`M=(w)/(mxxV(l)),0.25=(w)/(106xx0.25)`
w = 6.625 g.
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Knowledge Check

  • The amount of anhydrous Na_(2)CO_(3) present in 250 ml of 0.25 M solution of

    A
    6.225g
    B
    66.25g
    C
    6.0g
    D
    6.625g

  • Calculate the mass of anhydrous Na_2CO_3 required to prepare 250 ml 0.25 M solution .

    A
    6.225 g
    B
    66.25 g
    C
    6.0 g
    D
    6.625 g

  • The amount of H_2SO_4 present in 400 mL of 0.1 M solution of the acid is -

    A
    2.45 g
    B
    3.92 g
    C
    9.80 g
    D
    4.9 g
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