`6.02 xx 10^(20)` molecules of urea are present in 100 mL of its solution. The concentration of urea solution is
(Avogadro constant, `N_(A) = 6.02 xx 10^(23)mol^(-1))`

Options

A. `0.02M`
B. `0.01M`
C. `0.001M`
D. `0.1M`

Answer

B

Explanation

Mole of urea = `(6.02xx10^(20))/(6.02xx10^(23))=10^(-3)` moles
Conc. Of solution (in molarity) `=(10^(-3))/(100)xx1000=0.01M`.