If the concentration of glucose `(C_(6)H_(12)O_(6))` in blood is `0.9 "g L"^(-1)`, what will be the molarity of glucose in blood ?

Options

A. 5 M
B. 50 M
C. 0.005 M
D. 0.5 M

Answer

C

Explanation

In the given question, `0.9gL^(-1)` means that 1000 mL (or 1L) solution contains 0.9 g of glucose.
`therefore` Number of moles = 0.9 g glucose = `(0.9)/(180)` mol glucose
`=5xx10^(-3)` mol glucose
(where, molecular mass of glucose `(C_(6)H_(12)O_(6))=12xx6+12xx1+6xx16=180u`)
i.e., 1L solution contains 0.005 mole glucose or the molarity of glucose is 0.005 M.