The density (in g `mL^(-1))` of a `3.60M` sulphuric acid solution that is `29% H_(2)SO_(4)` (Molar mass `= 98 g mol^(-1))` by mass will be

Options

A. 1.64
B. 1.88
C. 1.22
D. 1.45

Answer

C

Explanation

Let the density of solution be ‘d’
Molarity of solution given = 3.6
i.e., 1 litre of solution contains 3.6 moles of `H_(2)SO_(4)`
or 1 litre of solution contains `3.6xx98g` of `H_(2)SO_(4)`
Since, the solution is 29% by mass
100 g solution contains 29 g `H_(2)SO_(4)`
`(100)/(d)`mL. solution contains 29 g of `H_(2)SO_(4)`
1000 mL solution contains `3.6xx98g` of `H_(2)SO_(4)`
`therefore 3.6xx98=(29xxd)/(100)xx1000`
d = 1.22.