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With 63 gm of oxalic acid how many litre...

With 63 gm of oxalic acid how many litres of `(N)/(10)` solution can be prepared

A

100 L

B

10 L

C

1 L

D

1000 L

Text Solution

Verified by Experts

The correct Answer is:
B
Normality `=(W)/((eq.wt)/("Vol"))xx1`
As normality is `(N)/(10)`
`therefore` eq. Wt. Of oxalic acid is 63.
`(1)/(10)=((63)/(63)xx1)/("Vol")` implies Vol = 10 L
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