The volume of water to be added to `100 cm^(3)` of 0.5 `NH_(2)SO_(4)` to get decinormal concentration is

Options

A. `400cm^(3)`
B. `500cm^(3)`
C. `450cm^(3)`
D. `100cm^(3)`

Answer

A

Explanation

Suppose the total volume of water = x
`therefore100cm^(3)xx0.5N=x xx0.1N`
`therefore x=(100xx0.5)/(0.1)=500cm^(3)`
Therefore the volume of water added
= Total volume `-100cm^(3)=500-100=400cm^(3)`.