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What weight of hydrated oxalic acid shou...

What weight of hydrated oxalic acid should be added for complete neutralisation of 100 ml of 0.2N - NaOH solution

A

0.45 g

B

0.90 g

C

1.08 g

D

1.26 g

Text Solution

Verified by Experts

The correct Answer is:
D
For complete neutralization equivalent of oxalic acid = equivalent of NaOH =
`(w)/(eq.wt)=(NV)/(1000)therefore(w)/(63)=(0.2xx1000)/(1000)impliesw=1.26g`
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