The molarity of 90% `H_(2)SO_(4)` solution is [density = 1.8 gm/ml]

Options

A. 1.8
B. 48.4
C. 91.83
D. 94.6

Answer

C

Explanation

The density of solution = 1.8 g /mL Weight of one litre of solution = 1800 g
`therefore` Weight of `H_(2)SO_(4)` in the solution = `(1800xx90)/(100)=1620g`
`therefore` Weight of solvent = 1800 - 1620 = 180 g
`therefore` Molarity = `(1620)/(98)xx(1000)/(180)=91.83`.