Calculate the molality of a solution that contains 51.2g of naphthalene, (`C_(10)H_(8)`) in 500 mL of carbon tetrachloride. The density of `C Cl_(4)` is 1.60 g/m

Options

A. 0.250 m
B. 0.500 m
C. 0.750 m
D. 0.840 m

Answer

B

Explanation

Volume of `C Cl_(4)=500mL`
Density of `C Cl_(4)=1.60 g//mL`
`therefore` Mass of `C Cl_(4)(w_(1))=500xx1.60=800g`
Mass of Naphthalene `(w_(2))=51.2g`
Now, `m=(w_(2)xx1000)/(M_(2)xxw_(1)("in g"))=(51.2xx1000)/(128xx800)=0.500m`