The weight percent of sucrose (formula weight = 342 g `"mol"^(-1)` in an aqueous solution is 3.42. The density of the solution is 1 g `mL^(-1)`, the concentration of sucrose in the solution in mol `L^(-1)` is

Options

A. `0.01`
B. `0.1`
C. `1.0`
D. 10

Answer

B

Explanation

3.42 g sucrose in 100 g solution
d = 1g / mL
`therefore d = ("Mass")/("Volume")`
Volume = `(100)/(1)=100mL`
Molarity = `(n)/(v)xx1000`
Molarity = `(3.42)/(342xx100)xx1000=0.1`.