What is the osmotic pressure of a `0.0020` mol `dm^(-3)` sucrose `(C_(12)H_(22)O_(11))` solution at `20^(@)C`? (Molar mass contant, `R = 8.314 JK^(-1) mol^(-1). 1 dm^(3) = 0.001 m^(3))`

Options

A. 4870 Pa
B. 4.87 Pa
C. 0.00487 Pa
D. 0.33 Pa

Answer

A

Explanation

`pi=CRT`
`C=.002mol dm^(-3)=.002 molL^(-1)`
`R=8.314JK^(-1) mol^(-1)`
(if pressure in k Pascals)
T implies 20 + 273 = 293 K
So, `pi=.002xx8.314xx293`
`=4.8720kPa=4872.0Pa`.