58.5 g of NaCl and 180 g of glucose were separately dissolved in 1000 mL of water. Identify the correct statement regarding the elevation of boiling point (bp) of the resulting solutions.

Options

A. NaCl solution will show higher elevation of b.pt.
B. Glucose solution will show higher elevation of b.pt.
C. Both the solutions will show equal elevation of b.pt.
D. The b.pt. of elevation will be shown by neither of the solutions

Answer

A

Explanation

`DeltaT_(b)=iK_(b)m`
For water implies 1000 mL = 1000g
Molality of NaCl = `(w//M.W.)/(W("solvent"))xx1000`
`=(58.5//58.5)/(1000)xx1000=1m`
Molality of glucose `=(180//180)/(1000)xx1000=1m`
i for NaCl = 2, i for glucose = 1
`DeltaT_(b)` for `NaClgtDeltaT_(b)` for glucose.