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After adding a solute freezing point of ...

After adding a solute freezing point of solution decreases to `-0.186 ^@C `. Calculate `DeltaT_b ` if `K_f = 1.86 ^@C`/ molal and `K_b = 0.52^@C`/ molal.

A

0.521

B

0.0521

C

1.86

D

0.0186

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaT_(f)=K_(f)xxmimplies0.186=1.86xxm`
So m = 0.1, Put the value of m in `DeltaT_(b)=K_(b)xxm`
`DeltaT_(b)=0.521xx(0.1)=0.0521`
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