K(f) of 1,4-"dioxane is" 4.9mol^(-1) for...

`K_(f) of 1,4-"dioxane is" 4.9mol^(-1)` for `1000g`.The depression in freezing point for a`0.001m` solution in dioxane is

`0.0049`

`4.9+0.001`

4.9

`0.49`

Text Solution

Verified by Experts

The correct Answer is:

`DeltaT=K_(f)xx` Molality = `4.9xx0.001=0.0049K`

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