In an experiment it is shown that `10 mL` of `0.05 M` solution of chloride required `10 mL` of `0.1 M` solution of `AgNO_(3)`, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine):

Options

A. `X_(2)Cl_(2)`
B. `XCl_(2)`
C. `XCl_(4)`
D. `X_(2)Cl`

Answer

B

Explanation

Millimoles of solution of chloride = `0.05 xx10 = 0.5` millimoles of `AgNO_(3)` solution = `10 xx 0.1 = 1` So, the millimoles of `AgNO_(3)` are double than the chloride solution.
`therefore XCl_(2)+2AgNO_(3)rarr2AgCl+X(NO_(3))_(2)`