Vapour pressure of `C CL_(4)` at `25^@C` is `143` mmHg 0.05g of a non-volatile solute (mol.wt.=`65`)is dissolved in `100ml C CL_(4)`. find the vapour pressure of the solution (density of `C CL_(4)=158g//cm^2`)

Options

A. 141.93 mm
B. 94.39 mm
C. 199.34 mm
D. 143.99 mm

Answer

A

Explanation

`(P^(0)-P)/(P^(0))=(n)/(n+N)`
`(143-P)/(143)=(0.5//65)/(0.5//65+158//154)`
[wt. of 100 mL `CCl_(4)` solution = 158 g]
[Molecular wt. `C Cl_(4)` of 154]
`(143-P)/(143)=(0.5)/(65)xx(65xx154)/(0.5xx154+158xx65)`
P = 141.93mm of Hg.