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A 5% solution (by mass) of cane sugar in...

A `5%` solution (by mass) of cane sugar in water has freezing point of 271 K. Calculate the freezing point of a 5% glucose (by mass) in water. The freezing point of pure water is 273.15 K.

A

271 K

B

273.15 K

C

269.07 K

D

277.23 K

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaT_(f)=K_(f)xx(w//m)xx1000`
`(DeltaT_(f_(2))//DeltaT_(f_(1)))=(m_(1)//m_(2))`.
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(a) A 10% solution (by mass) of sucrose in water has freezing point of 269.15K. Calculate the freezing point of 10% glucose in water, if the freezing point of pure water is 273.15K. Given: (molar mass of sucrose=342 g mol^(-1) ) (Mola mass of glucose =180g mol^(-1) ) (b) Define the following terms: (i) Molality (m) (ii) Abnormal molar mass

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