The following solutions were prepared by dissolving 10g of glucose in 250ml of water(`P_1)`, 10g of urea `(CH_4N_2O)` in 250ml of water`(P_2)` and 10g of sucrose `(C_(12)H_(22)O_(11))` in 250ml of water`(P_3)`. The right option for the decreasing order of osmotic pressure of those solutions is:

Options

A. `P_(1)gtP_(2)gtP_(3)`
B. `P_(2)gtP_(3)gtP_(1)`
C. `P_(3)gtP_(1)gtP_(2)`
D. `P_(2)gtP_(1)gtP_(3)`

Answer

D

Explanation

`pi=iCRT[pi=P]`
`P_(1)=1xx(10)/(180)xxRxxT` (For Glucose) = 0.05 RT
`P_(2)=1xx(10)/(60)xxRxxT` (For Urea) = 0.16 RT
`P_(3)=1xx(10)/(342)xxRxxT` (For Sucrose) = 0.03 RT
Hence, the decreasing order of osmotic pressure of these solution is :
`therefore P_(2)gtP_(1)gtP_(3)`.