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A gaseous hypothetical chemical equation...

A gaseous hypothetical chemical equation `2A hArr 4B+C` is carries out in a closed vessel. The concentration of `B` is found to increase by `5 xx 10^(-3) mol L^(-1)` in `10` second. The rate of appearance of `B` is

A

`5xx10^(-4)"mol l"^(-1)sec^(-1)`

B

`5xx10^(-5)"mol l"^(-1)sec^(-1)`

C

`6xx10^(-5)"mol l"^(-1)sec^(-1)`

D

`4xx10^(-4)"mol l"^(-1)sec^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
Increase in concentration of `B=5xx10^(-3)"mol l"^(-1)` Time = 10 sec
Rate of appearance of `B=("Increase of conc. B")/("Time taken")`
= `=(5xx10^(-3)"mol l"^(-1))/(10sec)=5xx10^(-4)"mol l"^(-1)"sec"^(-1)`
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