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The initial rate, -(d[A])/(dt) at t=o wa...

The initial rate, `-(d[A])/(dt)` at t=o was found to be `2.6xx10^(2)" mol "L^(-1)s^(_1)` for the reaction
`A+2Brarr"products"`
The initial rate, `-(d[B])/(dt),` at t=o is

A

`0.10"mol" L^(-1)s^(-1)`

B

`2.6xx10^(-2)"mol"L^(-1)s^(-1)`

C

`5.2xx10^(-2)"mol"L^(-1)s^(-1)`

D

`6.5xx10^(-3)"mol"L^(-1)s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`A+2B to` products
`-(d[A])/(dt)=(-d[B])/(2dt)`
`2.6xx10^(-2)"mol L"^(-1)s^(-1)=(-d[B])/(2dt)`
`-(d[B])/(dt)=2xx2.6xx10^(-2)`
= `5.2xx10^(-2)"mol L"^(-1)s^(-1)` .
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