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Rate law for the reaction, A + 2B to C i...

Rate law for the reaction, `A + 2B to C` is found to be
Rate `= k [A] [B]`
Concentration of reactant 'B' is doubled keeping the concentration of 'A' constant, the value of rate constant will be _______

A

The same

B

Doubled

C

Quadrupled

D

Halved

Text Solution

Verified by Experts

The correct Answer is:
B
Rate law can be written as
Rate = k[A][B]
Rate of reaction w.r.t. B is of first order .
`R_(1)=k[A][B]`
When concentration of reactant .B. is doubled then rate `(R_(2))`
`R_(2)=k[][2B]`
`R_(2)=2k[A][B]`
`R_(2)=2R_(1)`
Therefore, as concentration of B is doubled keeping the concentration of A constant rate of reaction doubles .
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