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In the synthesis of ammonia from nitroge...

In the synthesis of ammonia from nitrogen and hydrogen gases, if `6xx10^(-2)` mole of hydrogen disappears in 10 minutes, the number of moles of ammonia formed in 0.3 minutes is

A

`1.8xx10^(-2)`

B

`1.2xx10^(-3)`

C

`4xx10^(-2)`

D

`3.6xx10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`N_(2)+3H_(2) to 2NH_(3)`
`-([H_(2)])/(Deltat)=(3)/(2)([NH_(3)])/(Deltat)`
or `([NH_(3)])/(Deltat)=-(2)/(3)([H_(2)])/(Deltat)=(2)/(3)xx(6xx10^(-2))/(10)`
`[NH_(3)]=0.4xx10^(-2)xx10=4xx10^(-2)`
In 10 mins. No. of moles of `NH_(3)=4xx10^(-2)`
then in `0.3` `"min"=(4xx10^(-2)xx0.3)/(10)=1.2xx10^(-3)`
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