Home
Class 12
CHEMISTRY
A substance undergoes first order decomp...

A substance undergoes first order decomposition. The decomposition follows two parallel first order reaction as :

The precentage distribution of B and C are :

A

`75%` B and `25%` C

B

`80%` B and `20%` C

C

`60%` B and `40%` C

D

`90%` B and `10%` C

Text Solution

Verified by Experts

`%` distribution of `B=(k_(1))/(k_(1)+k_(2))xx100`
= `(1.26xx10^(-4))/(1.26xx10^(-4)+3.8xx10^(-4))xx100`
`B% = 76.83%`
`%` Distribution of `C=(k_(2))/(k_(1)+k_(2))xx100`
= `(3.8xx10^(-4))/(1.26xx10^(-4)+3.8xx10^(-4))xx100`
`C%=23.17%`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    ERRORLESS|Exercise NCERT BASED QUESTIONS (Rate Law and Rate Constant)|106 Videos
  • CHEMICAL KINETICS

    ERRORLESS|Exercise NCERT BASED QUESTIONS (Collision Theory, Energy of Activation and Arrhenius Equation)|54 Videos
  • CARBOXYLIC ACIDS

    ERRORLESS|Exercise Assertion & Reason|5 Videos
  • CHEMISTRY IN EVERYDAY LIFE

    ERRORLESS|Exercise Assertion & Reason|4 Videos

Similar Questions

Explore conceptually related problems

A substance undergoes first order decomposition. The decomposition follows two parallel first order reactions as The % distribution of B and C is ................ and .................. respectively.

A subtance undergoes first order decomposition involving two parallel first order reaction as : The mole percent of B in the products is :

A substance undergoes first order decomposition. The decomposition follows two parallel first order reactions as , k_(1)=1.26xx10^(-4)" sec"^(-1) and k_(2)=3.6xx10^(-5)" sec"^(-1) Calculate the % distribution of B & C.

The substance undergoes first order decomposition. The decomposition follows two parallel first order reactions as : K_(1)=1.26xx10^(-4) sec^(-1) and K_(2) =3.8xx10^(-5) sec^(-1) The percentage distribution of B and C

The substance undergoes first order decomposition.The decomposition follows two parallel first order reactons as : K_1=10^(-2) sec^(-1) and K_2=10^(-2)sec^(-1) If the corresponding activation energies of parallel reaction are 100 and 120 kJ "mol"^(-1) then the net activation energy of A is/are:

A substance undergoes first order decomposition. The decomposition follows two parallel first order reactions as : k_(1) =1.26xx10^(-4)s^(-1), k_(2) =3.8xx10^(-5) s^(-1) The percentage distribution of B and C are :

A substance undergoes first order decomposition. The decomposition follows two parallel first order reaction as: and KP_(1)=1.26xx10^(-4)sec^(-1) K_(2)=3.80xx10^(-5)sec^(-1) The percentage distribution of B and C are: